- in chemical reactions, usually one one chemical gets used up before the other
- the chemical used up first is called the limiting reactant
- one it's used up the reaction stops
- limiting reactants determines the quantity of products formed
- to fine the limiting reactant assume one reactant is used up. Determine how much of this reactant is required
2.5 mol of CuSo4 reacts with 2.5 mol of NaNO3. Determine the L.R and calculate how many moles Na2SO4 are formed.
CuSO4+ 2NaNO3= Na2SO4+Cu(NO3)2
2.5mol (CuSO4) x 2/1 = 5.0 mol of NaNO3 NaNO3 is L.R
2.5mol (NaNO3) x 1/2 = 1.25 mol Na2SO4
BY: KRYSTA DEL ROSARIO :)
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